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I am trying to create a countdown timer in Arduino that will start at the push of a button, and that will also abort at the push of the same button. The value is between 0 - 60 and set by a potentiometer. The problem I have so far is that I cannot exit the loop after it starts. I know that it can be done using the 'break', but I can't figure out where to put it that the result will be as desired. This is what I have so far:. For example, if I set the potentiometer to 5 and push the button I see 5, 4, 3, 2, 1, 0, off, but I cannot break out of it if I push the button again until it finishes.

How can I escape this loop on the push of a button? It is inside a function that gets called when the button is pushed. To break out of the loop, you simply have to add a break; statement inside that loop. But the problem is how to check for the condition that will help you break out of the loop?

You'd need to check again the input pin using the digitalRead inside the loop. But why check two times the state of one single button inside a simple algorithm? That's why I'm suggesting you another take on your problem, by using a single loopthe loop function, use a set of three state variables:.

I notice the post has been here for a year now, but just in case anyone is still looking for an answer You can always put delay code at the top of the method to avoid code repetition and avoid accidentally skipping it due to early break out of loop.

I know it has been a while since this was active, but a big issue I can see with the previous answer is the use of delays, where if I am reading it correctly it gives 1. A better answer would calculate the time since it last counted down and then count down if it is 1 second or above. It might be a bit off, but it is much closer to the 1 second. It also solves another issue that the button can only exist between these delays, giving a short time every 1.

This way the button is checked every loop and the loop is run continually rather than pausing for the second waiting for it to count down, and it will count every second. Learn more. How can I break this loop on a button press? Ask Question. Asked 6 years, 9 months ago. Active 5 years, 3 months ago. Viewed 30k times. Peter Mortensen Active Oldest Votes.

So now, there are only two possible scenarios: Press the button, countdown starts, countdown iterates, countdown ends and stops Press the button, countdown starts, countdown iterates, press the button, countdown stops If the potentiometer is at 0, the button is disabled. Thank you for your help Sir. The code you provided works after correcting a few typos :but the result is not as expected. Now the countdown goes down only if i keep the button pressed, which is still not good Any ideas on how to fix that as well?

HerrActress oh sorry, the reason was in my comments. The countdown starts but a button press does not stop itBy using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

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Change your preferences any time. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. In a C feel free to answer for other languages loop, what's the difference between break and continue as a means to leave the structure of the loop, and go to the next iteration? The break will cause the loop to exit on the first iteration - DoSomeThingWith will never be executed.

This here:. A really easy way to understand this is to place the word "loop" after each of the keywords. The terms now make sense if they are just read like everyday phrases.

break out of a loop arduino

In a for loop, continue jumps to the increment expression. I used to always get confused whether I should use break, or continue. This is what helps me remember:. There are more than a few people who don't like break and continue.

But I find that sometimes using one of them really simplifies things, especially if your language doesn't include a do-while or do-until style of loop. I tend to use break in loops that are searching a list for something. Once found, there's no point in continuing, so you might as well quit. I use continue when doing something with most elements of a list, but still want to skip over a few. The break statement also comes in handy when polling for a valid response from somebody or something.

Instead of:.

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The do-until loop that I mentioned before is the more elegant solution for that particular problem:.By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

The dark mode beta is finally here. Change your preferences any time. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. I am trying to create a countdown timer in Arduino that will start at the push of a button, and that will also abort at the push of the same button. The value is between 0 - 60 and set by a potentiometer.

The problem I have so far is that I cannot exit the loop after it starts. I know that it can be done using the 'break', but I can't figure out where to put it that the result will be as desired. This is what I have so far:. For example, if I set the potentiometer to 5 and push the button I see 5, 4, 3, 2, 1, 0, off, but I cannot break out of it if I push the button again until it finishes. How can I escape this loop on the push of a button?

It is inside a function that gets called when the button is pushed. To break out of the loop, you simply have to add a break; statement inside that loop. But the problem is how to check for the condition that will help you break out of the loop? You'd need to check again the input pin using the digitalRead inside the loop. But why check two times the state of one single button inside a simple algorithm? That's why I'm suggesting you another take on your problem, by using a single loopthe loop function, use a set of three state variables:.

I notice the post has been here for a year now, but just in case anyone is still looking for an answer You can always put delay code at the top of the method to avoid code repetition and avoid accidentally skipping it due to early break out of loop.

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I know it has been a while since this was active, but a big issue I can see with the previous answer is the use of delays, where if I am reading it correctly it gives 1. A better answer would calculate the time since it last counted down and then count down if it is 1 second or above. It might be a bit off, but it is much closer to the 1 second. It also solves another issue that the button can only exist between these delays, giving a short time every 1.

This way the button is checked every loop and the loop is run continually rather than pausing for the second waiting for it to count down, and it will count every second. Learn more. How can I break this loop on a button press?By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

The dark mode beta is finally here. Change your preferences any time. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. You will never leave this loop in order to be able to run a case such as Case 'D'. You will need to put an if statement within the while loop that checks for whatever you want to be true.

If it is true then you should break. Well, actually you can't break that while from outside since the program will only be running those instructions inside the while loop.

Maybe you should use another strategie. One would be the use of another variable that saves the option. Something like:. Looks like your "switch" case is a little malformed, I thought they always had to have a default case. The only issue with that is that while delaying between blinks its not testing for key presses, so to turn off the flag you'd have to hold 'D' for over two seconds, maybe even tap it. Its been a while since I used one of those keypads. Learn more. How to break infinite while in Arduino Ask Question.

Asked 4 years, 5 months ago. Active 22 days ago. Viewed 6k times. Brian 9, 7 7 gold badges 31 31 silver badges 43 43 bronze badges. Anas Anas 65 2 2 silver badges 8 8 bronze badges. You won't be able to make such a thing. Using an infinite loop in this way shouldn't be a good idea.

Try another way to control, for example, measureing time with millis. Active Oldest Votes. You can't exit the while loop therefore you will keep running the code digitalWrite 13,HIGH ; delay ; digitalWrite 13,LOW ; delay ; You will never leave this loop in order to be able to run a case such as Case 'D'.Starting Electronics Needs Your Help! It is that time of the year when we need to pay for web hosting and buy new components and equipment for new tutorials.

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Break- Continue - Goto / Estruturas de Controle Arduino

You may need to clear your browser cache to see the updates. The while loop is similar to the for loop that was explained in the previous part of this Arduino programming course. The main difference is that the while loop separates the elements of the for loop as will be shown. Another loop called the do while loop is also covered. The do while loop is always run at least once before any tests are done that could break program execution out of the loop.

The sketch that follows does exactly the same as the for loop sketch from part 7 of this course, except that it uses the while loop so that we can see the similarities between the two loops. The while loop starts with the while keyword followed by a test expression between opening and closing parentheses. Opening and closing braces denote the body of the loop. As with the for loop, the while loop has a test expression that will determine whether the statements in the loop will run or not.

If the test expression evaluates to truethe loop statements are run.

If the test expression evaluates to falsethe loop statements will not be run, but the statements that follow the closing brace of the loop will be run — i.

The for loop had an initialize expression as part of the loop. The while loop can use any variable from the sketch that contains a valid value.

In the example sketch, the variable used in the loop i must be initialized when it is defined, otherwise it will contain any random value. An increment expression was used in the for loop examples in the previous part of this course. In the while loop example, the increment expression is placed inside the loop body. Only when the variable i has been incremented to 10, will the loop expression evaluate to false and the loop will be exited.

In the example sketch below, the while loop is used to count up to twenty-five in fives by adding five to a variable each time through the loop. Can't see the video?By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

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If its true it will call the RelayOne function and open the solenoid valve inside the relayOne fucntion i have also code for waterflow sensor. This may not be a direct answer to the question, in the sense that I cannot tell you where exactly is the bug in your program.

But hopefully it will help you getting a program that does work. I tried to find the bug, but it's quite hard. As a general rule, a simple program is easier to get working than a complex program. So I would ask you: why don't you try something simple instead?

The first thing that stroke me is that it seems you did not realize that the pulse count from the flow sensor is a direct measurement of the volume that went through it. You are timing the pulses in order to convert a pulse count into a pulse rate, then you convert that into a flow rate, then you integrate the flow rate rate to get the volume.

All this is unnecessary complication: just count the pulses, the count is a water volume, albeit in an unusual unit. Second thing is the logic of the whole program. It should be clear at first sight under what conditions the watering starts and under what conditions it stops.

This is best done with a finite state machine with two state: either we are watering the plants or we are not. The state variable is then a boolean, and the logic could written along those lines:. Something explicit like this is generally easier to read, to understand and to debug. And likely to be less buggy in the first place.

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Third thing, you seems to be doing too much stuff at once: controlling two different pumps, monitoring a DHT sensor, updating the setpoints You should try to get a minimal program working, and only then start to add more stuff.

The more functionality you add, the more complex the program gets. Don't expect something complex to just work: you should really get a simple version working first, and only then build on that.

Here is a proposed simplified version for your program. Absolutely not tested: it is just meant to get you started. Note that the pulse count has to be read with interrupts disabled, but you should not detach the interrupt handler. Detaching the handler means you will miss pulses, wheres disabling the interrupts only delays their handling until you enable them again.By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

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Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. I'm trying to exit the void loop after an if statement within the loop returns true.

break out of a loop arduino

In other words, if the condition for the if statement is met, I want it to only run once and stop fully. This is used to control a DC motor with a potentiometer. So, as the potentiometer is HIGH, the dc motor should run for 1 second and stop fully and as the potentiometer is LOW the motor should run backward and stop fully.

I'm having trouble exiting the loop. Learn more.

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Asked 2 years, 4 months ago. Active 2 years, 2 months ago. Viewed 5k times.

break out of a loop arduino

Unclear - which if statement within the loop? Which loop? The function named loop or a loop within loop? The function named loop. The break exits the for loop. If you return from the void loop it will be called again. It's a function. Weather Vane how do I use the break command to execute that if statement then? Active Oldest Votes. Peter Peter 1. Mtt95dvlpr Mtt95dvlpr 1 1 silver badge 11 11 bronze badges.


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